The rotational speeds of four generators are listed in rpm (revolutions per minute). arrange the generators in order based on the electric fields they create. start with the weakest electric field and end with the strongest. assume that the generators are identical except for their speed.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.

the answer your looking for is c).