Consider the neutralization reaction 2hno3(aq)+ba(oh)2(aq)⟶2h2o(l)+ba(no 3)2(aq) 2hno3(aq)+ba(oh)2(aq)⟶2h2o(l)+ba(no 3)2(aq) a 0.110 l0.110 l sample of an unknown hno3hno3 solution required 51.9 ml51.9 ml of 0.100 m ba(oh)20.100 m ba(oh)2 for complete neutralization. what is the concentration of the hno3hno3 solution? concentration:

The concentration of solution will be 0.094 M.

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is

We are given:

Conversion factor: 1L = 1000 mL

Putting values in above equation, we get:

Hence, the concentration of solution will be 0.094 M.

thats how its supposed to be