If 5.00 grams of aluminum react with an excess of copper (ii) sulfate and the percentage yield is 63.4%, what is the mass of the copper produced? the other product is aluminum sulfate.

Answer : The mass of copper produced will be, 11.796 grams

Explanation : Given,

Mass of = 5 g

Molar mass of = 26.98 g/mole

Molar mass of = 63.66 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react to give 3 moles of

So, 0.185 moles of react to give moles of

Now we have to calculate the mass of .

The theoretical yield of Cu = 17.66 grams

Now we have to calculate the actual yield of Cu.

Now put all the given values in this formula, we get the actual yield of Cu.

Therefore, the mass of copper produced will be, 11.796 grams

the correct answer is option d

explanation:

i was wrong its d because they dont use cm when calculating square roots

l dont know l am s sorry