Amixture contained calcium carbonate and magnesium carbonate in unspecified proportions. a 7.85g sample of this mixture has reacted with excess hydrochloric acid, producing 1.94l of carbon dioxide at 25 degrees c and 785mmhg. what are the percentage of calcium carbonate and magnesium carbonate in the sample?

The percentage of calcium carbonate is 76.3% and magnesium carbonate is 23.7%.

Explanation:

produced ca be calculated from ideal gas equation:

P= Pressure of the gas = 785 mmHg = 1.03 atm    (760 mmHg= 1 atm)

V= Volume of the gas = 1.94 L

T= Temperature of the gas = 25°C=(25+273)K= 298 K   (0°C = 273 K)

R= Value of gas constant = 0.0821 Latm\K mol

Mass of

If the mass of calcium carbonate is x g , (7.85-x) g of magnesium carbonate is there.

As, 100 g of react to give 44 g of gas

So, x g of react to give of gas

The balanced chemical reaction will be:

As, 84 g of react to give 44 g of gas

So, of react to give of gas

By solving the terms, we get the value of x

x = 5.99 g

The mass of = x = 5.99 g

The mass of = 7.85 - 5.99 = 1.86 g

Now we have to calculate the percentage of magnesium carbonate.

Therefore, the percentage of calcium carbonate is 76.3% and magnesium carbonate is 23.7%.

answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: