Chemistry, 05.07.2019 18:20 brittnum9044
If the rate of a particular reaction is 4 ties faster at 373k that it was at 323k what is the activation energy for the reaction
Answers: 1
![\log \frac{k_2}{k_1}=\frac{E_a}{2.303\times R}[\frac{T_2-T_1}{T_2\times T_1}]](/tpl/images/0054/9720/494d5.png)
= Activation energy
= Temperature when rate of the reaction was 
= Temperature when rate of the reaction was 
![\log \frac{4k}{k}=\frac{E_a}{2.303\times 8.314 J /mol K}[\frac{373 K-323K}{373 K\times 323 K}]](/tpl/images/0054/9720/0db3f.png)
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If the rate of a particular reaction is 4 ties faster at 373k that it was at 323k what is the activa...
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