Asample containing only carbon, hydrogen, and silicon is subjected to elemental analysis. after complete combustion, a 0.7020 g sample of the compound yields 1.4 g of co2, 0.86 g of h2o, and 0.478 g of sio2. what is the empirical formula of the compound?

The empirical formula of compound is .

Explanation:

Mass of Sample= 0.702 g

Mass of = 1.4 g

Mass of = 0.86 g

Mass of = 0.478 g  

First we have to calculate moles of, and formed.

1. Moles of

Now , Moles of carbon == Moles of = 0.032

2.  Moles of =0.048mol

Now , Moles of hydrogen = Moles of =

3.  Moles of mol

Now , Moles of silicon = Moles of = 0.008 moles

Therefore, the ratio of number of moles of C : H : Si is  = 0.032 : 0.096 : 0.008

For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C=

For H =

For Si=

Thus, C: H: Si = 4 : 12 : 1

The simplest ratio represent empirical formula.

Hence, the empirical formula of compound is .

for points guys

i believe it is c.) 1575 j.