Water molecules around a hydrophobic molecule are (more) structured in the sense that their multiplicity w reduces from 6 to 3 (at or around room temperature) (a) what is the entropy change of such a water molecule. what is the corresponding free energy change? (b) suppose n is the number of water molecules adjacent to a hydrophobic molecule. what is the total free energy change due to water structuring? (c) assume that 10 water molecules cover an area of 1 nm2 around the hydrophobic molecule what is the free energy cost for exposing a hydrophobic molecule per area? answer this in units of kb t/nm2 (d) using your results in (a) or (b), explain why oil and water do not mix (at room temperature) note: you can answer (a) and (b) in terms of such parameters as kg (boltzmann constant) and t (the temperature).

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

12 is it do you think so

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole