Arigid vessel contains 3.98 kg of refrigerant-134a at 700 kpa and 60°c. determine the volume of the vessel and the total internal energy. m3 (round to four decimal places) kj (round to one decimal place)

The volume of the vessel is and total internal energy is 162.0 kJ.

Explanation:

or,

where,

P = pressure of container = 700 kPa

V = volume of container = ? L

m = Given mass of R-134a = 3.98 kg = 3980 g    (Conversion factor: 1kg = 1000 g)

M = Molar mass of R-134a = 102.03 g/mol

R = Gas constant =

T = temperature of container =

Putting values in above equation, we get:

Converting this value into , we use the conversion factor:

So,

or,

where,

U = total internal energy

m = given mass of R-134a = 3.98 kg = 3980 g  (Conversion factor: 1kg = 1000g)

M = molar mass of R-134a = 102.03 g/mol

R = Gas constant =

T = temperature =

Putting values in above equation, we get:

Converting this into kilo joules, we use the conversion factor:

1 kJ = 1000 J

So, 161994.6 J = 162.0 kJ

Hence, the volume of the vessel is and total internal energy is 162.0 kJ.

it means there are 3 atoms of oxygen