Formic acid (hco2h, ka = 1.8 × 10-4) is the principal component in the venom of stinging ants. what is the molarity of a formic acid solution if 25.00 ml of the formic acid solution requires 39.80 ml of 0.0567 m naoh to reach the equivalence point?

Answer : The molarity of a formic acid solution is, 0.0903 M

Explanation :

To calculate the molarity of formic acid, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of formic acid which is

are the n-factor, molarity and volume of sodium hydroxide base which is NaOH.

As we are given:

Now put all the given values in above equation, we get:

Hence, the molarity of a formic acid solution is, 0.0903 M

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