2nh_3(g) \longleftrightarrow n_2(g) + 3h_2(g) \hspace{30pt} k_p = 0.83 2 n h 3 ( g ) ⟷ n 2 ( g ) + 3 h 2 ( g ) k p = 0.83 consider your answers above, if the initial pressures for all three species is 1 atm what is the equilibrium pressure of h2? (hint: your quadratic will have two solutions, which one is impossible? )
Answers: 3
![\sqrt[x]{2} |3| { \sqrt[ log_{\%g}(3) ]{2} }^{3} {.}^{.83} \geqslant g \times \frac{.83}{0.83} \sqrt[ \geqslant ]{.83} 0.83 \times \frac{32e}{3} \geqslant log_{ \cos(?) }(?) \cos(?) log_{?}(?) e](/tpl/images/0056/8831/76eff.png)
![\sqrt[ \geqslant \sqrt[ log_{ \geqslant log_{ \cot( | log_{ \geqslant love \sqrt[ \geqslant | \sqrt[ \geqslant \geqslant \sqrt[ \geqslant \sqrt[ \geqslant ]{2.10} ]{3.8} ]{love} | ]{2 = 3} }(2 = 6) | ) }(love) }(.) ]{.} ]{.} love\%](/tpl/images/0056/8831/4c0f2.png)
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2nh_3(g) \longleftrightarrow n_2(g) + 3h_2(g) \hspace{30pt} k_p = 0.83 2 n h 3 ( g ) ⟷ n 2 ( g ) + 3...
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