Ascientist wants to make a solution of tribasic sodium phosphate, na3po4, for a laboratory experiment. how many grams of na3po4 will be needed to produce 375 ml of a solution that has a concentration of na+ ions of 1.50 m ?

The mass of that will be needed is 30.75 g.

Explanation:

The chemical equation for the ionization of sodium phosphate follows:

We are given:

Total concentration of Sodium ions in the solution = 1.5 M

So, concentration of sodium phosphate will be =

To calculate the moles of a solute, we use the equation:

We are given:

Volume of solution = 375 mL = 0.375 L   (Conversion factor: 1 L = 1000 mL)

Molarity of the solution = 0.5 moles/ L

Putting values in above equation, we get:

Now, calculating the mass of sodium phosphate using equation:

Molar mass of sodium phosphate = 164 g/mol

Moles of sodium phosphate = 0.1875 mol

Putting values in above equation, we get:

Hence, the mass of sodium phosphate used to prepare a solution will be 30.75 grams.