Y^2- 4x² - 4y—8x-16=0
transverse axis

Explanation:

The equation can be rearranged to standard form.

  (y^2 -4y) -4(x^2 +2x) = 16

  (y^2 -4y +4) -4(x^2 +2x +1) = 16 +4 -4

  (y -2)^2 -4(x +1)^2 = 16

  (y -2)^2 /16 -(x +1)^2/4 = 1

This is of the form ...

  (y -k)^2/a^2 -(x -h)^2/b^2 = 1

where the transverse axis is 2a and the center is (h, k). Here, a=4, so 2a = 8.

The transverse axis is a vertical line segment of length 8, centered on (-1, 2).

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.

6.4 cm (max) - 25 cm (min)