10 gram of caco3 contains how many moles?
a) 1
b) 0.01 c) 0.1
d) 0.001

C, 0.1 mol.

Explanation:

According to the periodic table, the molar mass of Ca is 40.1, C is 12.0, O is 16.0,

so the molar mass of CaCO3 is 40.1 + 12.0 + 16.0 x 3 = 100.1

Using this formula:

no. of moles = mass / molar mass

No. of moles of CaCO3 = 10 / 100.1

= 0.1 mol (corrected to 1 d.p.)

Therefore, the answer is C, 0.1 mol.

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.

i belive it is water