Part 1. determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 l at 287 k and 0.850 atm. show your work.
part 2. if this sample was placed under extremely low temperature, describe how the actual volume would compare to the predicted volume. explain your answer.

Explanation:

Given parameters:

Mass of the sample = 0.622g

Volume of the gas = 2.4L

Temperature = 287K

Pressure of the gas = 0.85atm

Unknown

Molar mass of the gas = ?

Solution

To find the molar mass of the gas, we first assume that the gas in question is an ideal gas i.e. it obeys Boyle's and Charles's law.

On this premise, we can find the unknown which is the molar mass of the gas.

   Solving for number of moles:

   The ideal gas equation is given as PV = nRT

  We make the unknown "n" the subject of the equation

                           n =

     R is the gas constant whose value is 0.082atmdm³mol⁻¹K⁻¹

                n =  

                n = = 0.087mole

                       molar mass =  

                    molar mass =   =7.15gmol⁻¹

Part 2:

If the sample was placed under a low temperature, we want to consider what would happen to the volume:

Since we assume that the gas is an ideal gas, we can explain what will happen to the gas using Charles's law. The law states that "The volume of a fixed mass of a gas varies directly as its absolute temperature if the pressure is constant".

  If we assume the pressure is constant for this gas, the volume of the gas would decrease as the temperature becomes lower. We would get lower values for both actual volume and predicted volume.

a electronegativity decreases beacuse the size of nucleus is bigger.