2al(s)+fe2o3(s)−→−heatal2o3(s)+2fe( l) 2al(s)+fe2o3(s)→heatal2o3(s)+2fe(l) if 26.1 kg al26.1 kg al reacts with an excess of fe2o3,fe2o3, how many kilograms of al2o3al2o3 will be produced?

Answer : The mass of produced will be, 49.32 Kg

Explanation : Given,

Mass of = 26.1 Kg  = 26100 g

Molar mass of = 26.98 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of .

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 2 moles of react to give 1 mole of

So, 967.38 moles of react to give moles of

Now we have to calculate the mass of .

Therefore, the mass of produced will be, 49.32 Kg

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be