A50.0-g ball of copper has a net charge of 2.00 µc . what fraction of the copper’s electrons has been removed? (each copper atom has 29 protons, and copper has an atomic mass of 63.5.)

The fraction of the copper’s electrons removed is .

Explanation:

Mass of copper ball = 50.0 g

Moles of copper =

1 mole =

Number of copper atoms =

1 atom of copper has 29 protons

Total number of protons in 50.0 g of copper =

Since an atom is a neutral specie which means number of protons are equal to number of electrons.

Total number of electrons = ....(1)

Net charge on the copper ball =

Q=Ne

Q = Total charge

N = Number of electrons

e = charge on an electron =

Total number of electrons removed = N =

Fraction of the copper’s electrons has been removed:

The fraction of the copper’s electrons removed is .

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