The reaction between ethyl bromide (c2h5br) and hydroxide ion in ethyl alcohol at 330 k, c2h5br(alc) + oh-(alc) --> c2h5oh(l) + br-(alc), is first order each in ethyl bromide and hydroxide ion. when [c2h5br] is 0.0477 m and [oh-] is 0.100 m, the rate of disappearance of ethyl bromide is 1.7 x 10^-7 m/s.
what is the value of the rate constant?
k=?

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Given: Order with respect to = 1

Order with respect to = 1

Thus rate law is:

k= rate constant

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

Given:

Putting in the values we get:

Thus the value of the rate constant is

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.