Part one.) estimate the value of the equilibrium constant at 640 k for each of the following reactions. δg∘f for brcl(g) is −1.0 kj/mol. the standard molar entropy, s∘, for brcl(g) is 240.0 j/mol⋅k.
a.) 2no2(g)⇌n2o4(g). δh∘f for n2o4(g) is 9.16 kj/mol.
k= ?
b.) br2(g)+cl2(g)⇌2brcl(g) .δh∘f for brcl(g) is 14.6 kj/mol.
k=?
part two.) estimate the value of the equilibrium constant at 675 k for each of the following reactions. δg∘f for brcl(g) is −1.0 kj/mol. the standard molar entropy, s∘, for brcl(g) is 240.0 j/mol⋅k.
a.) 2no2(g)⇌n2o4(g). δh∘f for n2o4(g) is 9.16 kj/mol.
k= ?
b.) br2(g)+cl2(g)⇌2brcl(g) .δh∘f for brcl(g) is 14.6 kj/mol.
k=?

oh it is true if thats what you are asking

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i  

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.