"a chiral alkyne a with molecular formula c6h10 is reduced with h2 and lindlar catalyst to b having the r configuration at its stereogenic center. what are the structures of a and b? be sure to answer all parts."

Kindly find the structure of A and B in attachment.

Explanation:

Lindlars catalyst is basically a palladium metal based catalyst which reduces specifically the alkynes to just alkenes and only reduce them in cis manner.

The palladium catalyst is poisoned by lead or quinoline so that the reduction reaction can be stopped at a point when alkynes are just reduced to alkenes because palladium in presence of hydrogen reduces the alkyne completely to alkane.

So lindlars catalys is very specific in its action and even in terms of stereochemistry as it only reduces alkynes to alkenes and the stereochemistry of reduced alkyne is cis.

The general formula of lindlars catalyst is : 5%Pd-CaCO3,Pb(OCOCH3)2 and quinoline.

A chiral alkyne would have all 4 different substituents present at the carbon next to triple bond.

since the reduction of chiral alkyne A would be done using Lindlars catalyst hence the reduced product formed would have Cis -stereochemistry.

The structures of A&B are drawn in attachments. Kindly find in attachment.

the correct name for the n3 ion is azide. azide is a polyatomic anion with a -1 charge and is written as n3 -1. it consists of three nitrogen atoms bonded together. hope i . let me know if you need anything else.

i have no clue hope you find the answer