Determine how many grams of silver would be produced, if 12.83 x 10^23 atoms of copper react with an excess of silver nitrate. given the equation: cu + 2agno3 -> cu(no3)2 + 2ag avogadro's number: 6.02 x 1023

The amount of silver produced in the given reaction is 459.63 g.

Explanation:

According to mole concept:

1 mole of an atom contains number of atoms.

For the given chemical equation:

By Stoichiometry of the reaction:

1 mole of copper produces 2 moles of silver.

This means that, number of atoms of copper produces number of atoms of silver.

So, number of atoms of copper will produce = number of atoms of silver.

We know that:

Mass of 1 mole of silver = 107.87 g

Using mole concept:

If, number of atoms occupies 107.87 grams of silver atom.

So, number of atoms will occupy =

Hence, the amount of silver produced in the given reaction is 459.63 g.

can you attach a picture of the lettuce? : )

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.