For the first-order reaction, 2 n2o(g) → 2 n2(g) + o2(g), what is the concentration of n2o after 3 half-lives if 0.25 mol of n2o is initially placed into a 1.00-l reaction vessel?

The concentration of after 3 half-lives is 0.03125 M.

Explanation:

We are given:

Moles of = 0.25 moles

Volume of solution = 1 L

Putting values in above equation, we get:

where,

a = concentration of reactant left after n-half lives = ?

= Initial concentration of the reactant =  0.25 mol/L

n = number of half lives  = 3

Putting values in above equation, we get:

Hence, the concentration of after 3 half-lives is 0.03125 M.

3

explanation:

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.