Diatomic iodine [i2] decomposes at high temperature to form i atoms according to the reaction i2(g)⇌2i(g), kc = 0.011 at 1200∘c in an equilibrium mixture, the concentration of i2 is 0.10 m. what is the equilibrium concentration of i? express your answer using two significant figures.

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

Given:

= 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

So,

Thus, The concentration of I at equilibrium = 3.3166×10⁻² M

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."

c, liquids evaporate, creating a gas