The arrhenius equation shows the relationship between the rate constant k and the temperature t in kelvins and is typically written as k=ae−ea/rt where r is the gas constant (8.314 j/mol⋅k), a is a constant called the frequency factor, and ea is the activation energy for the reaction. however, a more practical form of this equation is lnk2k1=ear(1t1−1t2) which is mathmatically equivalent to lnk1k2=ear(1t2−1t1) where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (t1 and t2).part athe activation energy of a certain reaction is 44.8 kj/mol . at 28 ∘c , the rate constant is 0.0180s−1. at what temperature in degrees celsius would this reaction go twice as fast? express your answer with the appropriate units. part b given that the initial rate constant is 0.0180s−1 at an initial temperature of 28 ∘c , what would the rate constant be at a temperature of 190 ∘c for the same reaction described in part a? express your answer with the appropriate units.