In the laboratory, a general chemistry student measured the ph of a 0.529 m aqueous solution of phenol (a weak acid), c6h5oh to be 5.153. use the information she obtained to determine the ka for this acid.

The dissociation constant of phenol from given information is .

Explanation:

The measured pH of the solution = 5.153

Initially      c

At eq'm   c-x       x  x

The expression of dissociation constant is given as:

Concentration of phenoxide ions and hydrogen ions are equal to x.

The dissociation constant of phenol from given information is .

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%

points

explanation: