Use tabulated standard electrode potentials to calculate the standard cell potential for the following reaction occurring in an electrochemical cell at 25 ∘c: 3pb2+(aq)+2cr(s)→3pb(s)+2cr3+(aq)(n ote that the equation is balanced.)

Answer : The standard cell potential of the reaction is, -1.46 V

Explanation :

The given balanced cell reaction is,  

Here, chromium (Cr) undergoes oxidation by loss of electrons and act as an anode. Lead (Pb) undergoes reduction by gain of electrons and thus act as cathode.

The standard values of cell potentials are:

Standard reduction potential of lead

Standard reduction potential of chromium

Now we have to calculate the standard cell potential for the following reaction.

Therefore, the standard cell potential of the reaction is, -1.46 V

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.