Triglycerides look like the letter "e" because they contain the following components
a. four fatty acid chains, a glycerol and a phosphate group
b. two fatty acid chains, a simple sugar and a nitrogenous base
c. three fatty acid chains and a 'backbone' of glycerol
d. three 6-carbon rings attached to one 5-carbon ring ("3 bedrooms and a bath")

c. Three fatty acid chains and a 'backbone' of glycerol

Explanation:

A triglyceride is ester which is derived from glycerol and three (may be different or same) fatty acids. The name is thus derived as tri ( 3 fatty acids) - and glyceride (glycerol backbone). Triglycerides are main constituents of the body fat in human body and other vertebrates.

Triglycerides are the tri-esters which consist of glycerol attached to 3 molecules of fatty acid. Alcohols consists of hydroxyl group. Organic acids consists of carboxyl group. Alcohols and organic acids join to form esters. The molecule of glycerol has 3 hydroxyl groups which are bonded to three fatty acid molecules via ester bonds.

yes

explanation:

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given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g