Abuffer is prepared by mixing 204.0 ml of 0.452 mol/l hydrochloric acid (hci) and 500.0 ml of 0.400 mol/l sodium acetate (nachco2, naac). what is the ph of the above buffer solution?

pH of buffer is 4.81

Explanation:

The reaction between HCl and sodium acetate will product acetic acid. The presence of weak acid (acetic acid) and its salt will make a buffer.

The reaction will be:

Thus one mole each of HCl and acetate will give one mole of acetic acid.

The moles of HCl present = molarity X volume = 0.452 X 0.204 =0.092

moles of acetic acid formed on reaction of HCl with acetate = 0.092

Initial moles of sodium acetate present = molarity X volume = 0.4X0.5 =0.2

moles of sodium acetate left =0.108 mol

the pKa of acetic acid =4.74

The pH of buffer is calculated using Henderson Hassalbalch's equation :

pH = pKa + log

r just means there's a number of carbon in teh chain. for example rcooh means that after x number of carbon, the chain ends with cooh.

explanation:

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