He combustion of propane (c3h8) is given by the balanced chemical equation c_3h_8+5o_2\longrightarrow3co_2+4h_ 2o c 3 h 8 + 5 o 2 ⟶ 3 c o 2 + 4 h 2 o how many grams of carbon dioxide gas (co2) are produced burning 97 g of propane? round your answer to the nearest gram.

290 grams

Explanation:

Let's begin by writing the balanced chemical equations:

Then we calculate the number of moles in 97g of propane.

n(propane)=

According to the balanced chemical equation, one mole of propane produces 3 moles of carbon dioxide. So the available number of moles of propane must be multiplied by three to work out the number of carbon dioxide produced.

n(carbon dioxide)= 2.1995mol*3 = 6.5985mol

mass(carbon dioxide) = moles * molar mass

                                   = 6.5985 mol * 44.01 g/mol

                                   = 290 grams

the answer is the first option

explanation:

just googled it m8. not that hard

lol