What is the ph of a 0.033 m koh solution

p
H
≈
11.5
Explanation:
When put in water, the
K
O
H
dissolves into
K
+
and
O
H
−
ions, with the latter increasing the
p
H
of the solution.
As hydroxides can be considered strong bases, it will completely dissociate into the water solution, and form an equal amount of moles of hydroxide ions:
0.003 mol of
O
H
−
.
Now,
p
O
H
=
−
log
[
O
H
−
]

p
O
H
=
2.522
And if we assume this is done under standard conditions:
p
O
H
+
p
H
=
14

p
H
=
14
−
2.522

p
H
≈
11.5

Hope it helped
Have a nice day☀️

This would be canberra.