When 10.0 grams of ch4 reacts completely with 40.0 grams of o2 such that there are no reactants left over, 27.5 grams of carbon dioxide are formed. how many grams of water are formed? ch4+ 2o2 → co2 + 2h2o

Explanation:

We know we will need an equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:      16.04    32.00  44.01   18.02

             CH₄  +  2O₂  →  CO₂ + 2H₂O

m/g:      10.0      40.0

1. Moles of CH₄

2. Mass of CO₂

(i) Calculate the moles of CO₂

The molar ratio is (1 mol CO₂ /1 mol CH₄)

(ii) Calculate the mass of CO₂

3. Mass of H₂O

(i) Calculate the moles of H₂O

The molar ratio is (2 mol H₂O /1 mol CH₄)

(ii) Calculate the mass of H₂O

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).

it takes on an electronical energy