Gallium is produced by the electrolysis of a solution made by dissolving gallium oxide in concentrated naoh(aq). calculate the amount of ga(s) that can be deposited from a ga(iii) solution using a current of 0.870 a that flows for 20.0 min.

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.

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The answer is 5 10 15

The chemical equation is ca(oh)2(s) + h2so4(aq) --> + h2o(l) in low concentrations it will stay in elucidation. at higher concentrations it will be precipitous.the oh- on the left responds with the h+ on the left to make hoh (h2o) as a produce. there's no oh- on the right hand side. so it should look like this:   ca2+ + 2oh- + 2h+ + so4^2- > caso4(s) + 2h2o(l)  hope this ! and mark me as brainliest if you dont mind : )