Part complete when a 235 92u nucleus is bombarded by neutrons (10n) it undergoes a fission reaction, resulting in the formation of two new nuclei and neutrons. the following equation is an example of one such fission process: 235 92u+10n→azba+9436kr+310n
enter the isotope symbol for the barium (ba) nucleus in this reaction. in another process in which 235 92u undergoes neutron bombardment, the following reaction occurs: 235 92u+10n --> azsr+143 54xe+310nenter the isotope symbol for the strontium (sr) nucleus in this reaction.

The isotopic symbol of barium is and that of strontium is

Explanation:

Nuclear fission reactions are defined as the reactions in which a heavier nuclei breaks down in two or more smaller nuclei.

In a nuclear reaction, the total mass and total atomic number remains the same.

Total mass on reactant side = total mass on product side

235 + 1 = A + 94 + 3

A = 139

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 36 + 0

Z = 56

The isotopic symbol of barium is

Total mass on reactant side = total mass on product side

235 + 1 = A + 143 + 3

A = 90

Total atomic number on reactant side = total atomic number on product side

92 + 0 = Z + 54 + 0

Z = 38

The isotopic symbol of strontium is

Hence, the isotopic symbol of barium is and that of strontium is

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