For the reaction 2na + cl2 → 2nacl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?

1019.27 g.

Explanation:

2Na + Cl₂ → 2NaCl,

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na = (1 mol)(57.5 mol)/((2 mol) = 28.75 mol.

∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) = (28.75 mol)(35.453 g/mol) = 1019.27 g.

nacl is added to the aqueous of what? ? in order to get a proper answer you have to specify the exact composition of the aqueous solution.