How many moles of hcl are present in 1.2 l of a 1.84 m hcl solution?
select one:
a. 17
b. 1.7e4
c. 20
d. 620

2.21 moles of HCl are present in 1.2 L of a 1.84 M HCl solution

Explanation:

Molarity (M),

Molality (m),

Normality (N),

Mass %,

Parts per million(ppm), billion(ppb), thousands(ppt) are some of the terms we use to represent the concentration of the solution that is to represent the amount of solute present in a solvent.

Molarity is moles of solute present in 1L of the solution.

The formula to find Molarity is  

and its unit is mol/L

Rearranging the formula

We get                        

moles  = Molarity × Volume

Plugging in the values  

(Answer)

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole