! im in desperate need! too hard for me to answer. the solvay process for the manufacture of sodium carbonate begins by passing ammonia and carbon dioxide through a solution of sodium chloride to
make sodium bicarbonate and ammonium chloride. the equation for this reaction is
h2o + nacl + nh3 + co2 + nh4cl + nahco3
in the next step, sodium bicarbonate is heated to give sodium carbonate and two gases, carbon dioxide and steam.
2nahco3 → na2co3 + co2 + h20
what is the theoretical yield of sodium carbonate, expressed in grams, if 120.0 g of nacl were used in the first reaction?
if 85.40 g of na2co3 was obtained, what was the percentage yield?

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole