Agaseous hydrogen and carbon containing compound is decomposed and formed to contain 82.66% carbon and 17.34% hydrogen by mass. the mass of 158 ml of the gas, measured at 556 mmhg and 25c, is 275g. what is the molecular formula of the compound?

Explanation:

Mole percentage of carbon =

                                              =

                                              = 6.89

Mole percentage of hydrogen =

                                               =

                                               = 17.34

Now, dividing mole percentage of both the atoms by 6.89.

Then,     C = 1 and H = = 2.5

Hence, empirical formula is .

As, it is given that P = 556 mm Hg. Convert mm Hg into atm as follows.

                             = 0.7316 atm

Volume is given as 158 mL. So, in liter volume is equals 0.158 L.

According to ideal gas equation, PV = nRT

                   molar mass = 58.2 g

Hence, molecular weight of is = 29.

Therefore, = 58

                               29 × n = 58

                                   n = 2

Thus, molecular formula of the compound is .