What is the temperature of 13.3 moles of carbon dioxide that occupies 6 m3 and applies a pressure of 23 kpa to its container?

T = 1248 K

Explanation:

We can calculate the T, by using the ideal gas law:

PV = nRT

Where we have:  

The pressure P, volume V, and temperature T, R is the gas constant, and n is the number of moles of the gas.  

According to the international unit systems R is 8.314 J/(K·mol)

With this value the P unit will be Pa and the V unit will be m³.  

Then,  

T = PV / nR  

T = (23 × 1000 × 6) / (13.3 × 8.314)  

T = 1248 K

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

um i think it might be a car?