If you take organic chemistry laboratory (chm2211l) you will learn the term reflux. a reaction is considered to be at reflux when it is set at the boiling point of your solvent. a. in order to bring 74.81 ml of chloroform (density = 1.4832 g/cm3 , c = 0.96 j/g*k ) to reflux from room temperature (25 oc) it requires 1.46 kj of energy. what will be the temperature (in of) of the chloroform?

Answer : The temperature of the chloroform will be,

Explanation :

First we have to calculate the mass of chloroform.

conversion used :

Now we have to calculate the temperature of the chloroform.

Formula used :

where,

q = amount of heat or energy = 1.46 kJ = 1460 J   (1 kJ = 1000 J)

= specific heat capacity =

m = mass of substance = 110.958 g

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get:

Now we have to convert the temperature from Kelvin to Fahrenheit.

The conversion used for the temperature from Kelvin to Fahrenheit is:

As we know that, or,

 ...........(1)

Now put the value of temperature of Kelvin in (1), we get:

Therefore, the temperature of the chloroform will be,

a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.