The solubility of pb(no 3) 2 is 55 grams per 100 g h 2o at 20°c. which term would properly describe a solution where 44 grams of pb(no 3) 2 is added to 100 grams of water at this temperature?

The solution is unsaturated.

Explanation:

Amount dissolved > Maximum solubility limit, the solution is saturated.

Amount dissolved < Maximum solubility limit, the solution is unsaturated.

44 g of Pb(NO₃)₂ is added to 100 g of water, the solution is:

Solubility of the Pb(NO₃)₂ given at 20 °C = 55 g/100 g water.

It means:

100 g of water can dissolve maximum of 55 g of  Pb(NO₃)₂

It means,

Maximum amount of Pb(NO₃)₂ that can be dissolved = 55 g

Actual amount dissolved = 44 g

Since,  

Amount dissolved < Maximum solubility limit

44 g > 55 g

According to definition, the solution is unsaturated.