Write the products in the products column (c-c represents a triple bond in all the 4 examples) reactant reagents products ch3-c-c-ch2ch3 a. h20, h2804 b. 1. r2bh/thf 2. oh-, h202, h20 ch3-c-c-h h20, h2s04, hgso4 a. h20, h2s04 ch3-c-c-h b. 1. r2bh/thf 2. oh-, h2o2, h2o 1. nanh2 ch3-c-c-h 2. ch3ch2ch2ch2br

describe matter a earth

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

answer: c.

explanation:

the objects have the same charge.