Give the oxidation state of the metal, number of d electrons, and the number of unpaired electrons predicted for [co(nh3)6]cl3.

Oxidation state: +3

No of d electrons: 6

Unpaired electrons : 4

Explanation:

Oxidation state: X+6(0)=+3

X=+3

And Co has Atomic number 27

And here it is Co+3 hence [Ar]3d6

Since H2O is weak field ligand no pairing of Electrons involved. Hence there are 4 unpaired electrons. 2 in t2g and 2 in eg orbitals.

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