Indicate the coordination number for the central metal atom in each of the following coordination compounds:
(a) [pt(h2o)2br2]
(b) [pt(nh3)(py)(cl)(br)] (py = pyridine, c5h5n)
(c) [zn(nh3)2cl2]
(d) [zn(nh3)(py)(cl)(br)]
(e) [ni(h2o)4cl2]
(f) [fe(en)2(cn)2]+ (en = ethylenediamine, c2h8n2)

A. 4, since all 4 ligands (2 H2O&2Br) are monodentate hence 4x1=4

B. 4, (4x1=4)

C. 4(4x1=4)

D. 4(4x1=4)

E. 6(6x1=6)

F. 6(2(2)+2(1)=4+2=6) en is bidentate ligand

Explanation:

Coordination number is equal to number of ligands surrounded the metal atom.

Coordination number= No of ligands X denticity

Denticity is nothing but nature of ligands like mono, bi dentate, or tetrads rate etc.