The mercury content of a stream was belived to be above the minimum considered safe part per billion (ppb) by weight. an analysis indicated that the concentration was 0.68 parts per billion. what quantity of mercury in grams was persent in 15.0 l of the water, the density of which is 0.998 g/ml? (1 ppb hg = 1nghg/1g water)

Quantity of Hg in 15.00 L water = 1.0*10^-5 g

Explanation:

Given:

Concentration of Hg = 0.68 parts per billion (ppb)

Volume of water = 15.0 L

Density of water = 0.998 g/ml

To determine:

The amount of Hg in 15.0 L of water

Calculation:

1 ppb = 1 nanogram (ng) solute/1 g water

1 ng = 10⁻⁹ g

0.68 ppb = 0.68 ngHg/1 g water = 0.68*10⁻⁹g Hg/ 1g water

The amount of Hg in the above mass of water would be:

=

thats how its supposed to be