Express the freezing point of water (0â°c), the boiling point of water (100â°c), and the range spanned by the two temperatures using the kelvin scale.

The freezing point of water is 273 K and boiling point of water is 373 K.

The range spanned by the two temperatures using the Kelvin scale is 100 K.

Explanation:

The freezing point of water = 0°C

The boiling point of water = 100°C

Conversion from degree Celsius to Kelvins

The freezing point of water in Kelvins = 0°C=

The boiling point of water in Kelvins =100 0°C=

Range spanned = 100°C - 0°C = 273 K- 373 K = 100 K

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%