The elements sulfur and oxygen can form a variety of different compounds, the most common of which are s02 and s03. samples of these two compounds, were decomposed into their constituent elements. one produced 1.002 g s for every gram of o; the other produced 0.668 g s for every gram of o. show that these results are consistent with the law of multiple proportions.

Explanation:

The law of multiple proportions say that two elements, A and B, are able to combine with each other to form distinct compounds, the different masses of B that bind to a certain mass of A, are in relation of integers and simple numbers.

2SO₂  → S₂ + 2O₂

Mass S₂=2 . 32g= 64g

Mass 2O₂=4 . 16g=64g

∴ 64/64=1 ⇒ One produced 1.002 g S for every gram of O, the relation is 1:1

2SO₃ → S₂ + 3O₂

Mass S₂=2 . 32g= 64g

Mass 3O₂=6 . 16g=96g

∴ 64/96= 2/3 ⇒ It is produced 0.668 g S for every gram of O, the relation is 2:3.

To sum up, these results are consistent with the law of multiple proportions because the results are integers and simple numbers.

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answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.