How many grams of naoh were dissolved to make a 1.25 l solution of 2.92 m naoh?

Explanation:

1) Data:

a) mass of solute = ?

b) volume of solution = 1.25 liter

c) M = 2.92 mol/liter

d) solute NaOH

2) Formulae:

a) Molarity, M = number of moles of solute / volume of solution in liters

b) mass in grams = molar mass × number of moles

3) Solution:

a) Calculate number of moles of solute:

        ⇒ number of moles of solute = M × volume of solution in liters

        ⇒ number of moles of solute = 2.92 mol/liter × 1.25 liter = 3.65 mol

b) Molar mass of NaOH = 39.997 g/mol (you can take this number from internet or calculate it using the atomic masses of Na, O, and H).

c) Calculate the mass of solute:

The answer must be reported with 3 significant figures, so it is 146. g.

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm