How many ul are present in 250 ml of h20? (1 ul = 10^-6 liters)

250000 μL

Explanation:

If         1 L = 1000 mL

Then  X L = 250 mL

X = (1 × 250) / 1000 = 0.25 L

Now we can calculate the number of microliters (μL) in 0.25 L:

if        1 μL = 10⁻⁶ L

then   X μL = 0.25 L

X = (1 × 0.25) / 10⁻⁶  =250000 μL

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :