Amixture containing kclo3,k2co3,khco3, and kcl was heated, producing co2,o2, and h2o gases according to the following equations: 2kclo3(s)? 2kcl(s)+3o2(g)2khco3(s)? k2o(s)+h2o(g)+2co2(g)k2co3(s)? k2o(s)+co2(g)the kcl does not react under the conditions of the reaction. 100.0 g of the mixture produces 1.90 g of h2o, 13.64 of co2, and 4.10 g of o2. (assume complete decomposition of the mixture.)1. how many grams of kclo3 were in the original mixture? 2.how many grams of khco3 were in the original mixture?

For 1: The mass of in the original mixture is 10.46 g

For 2: The mass of in the original mixture is 21.11 g

Explanation:

We are given:

Mass of water = 1.90 g

Mass of carbon dioxide = 13.64 g

Mass of oxygen = 4.10 g

The given chemical reaction for decomposition of follows:

By Stoichiometry of the reaction:

of oxygen is produced when of potassium chlorate is decomposed.

So, 4.10 g of oxygen will be produced when = of potassium chlorate is decomposed.

Amount of in the mixture = 10.46 g

The given chemical reaction for decomposition of follows:

By Stoichiometry of the reaction:

18 g of water is produced when of potassium bicarbonate is decomposed.

So, 1.90 g of water will be produced when = of potassium bicarbonate is decomposed.

Amount of in the mixture = 21.11 g

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b