Calculate the ph of a cu-h2 cell (e° = 0.34 v) if the emf is 0.45 volts and the [cu2 is 0.50 m hint: first write the oxidation and reduction half-reactions and determine which direction is spontaneous. determine if 2- cu and h are on the product or the reactant side before you start calculating.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.