For a particular redox reaction so_3^2-– is oxidized to so_4^2- and cu^+2 is reduced to cu . complete and balance the equation for this reaction in basic solution. phases are optional.

SO₃²⁻ + Cu²⁺ + 2OH⁻ ⟶ Cu + SO₄²⁻ + H₂O

Explanation:

I find that the easiest way to balance an equation in basic solution is first to balance as if it were in acid and then convert to base.

Your skeleton equation is

SO₃²⁻ + Cu²⁺ ⟶ SO₄²⁻ + Cu

1. Separate the reaction into two half-reactions

SO₃²⁻ ⟶ SO₄²⁻

Cu²⁺ ⟶ Cu

2. Balance all atoms other than O and H

Done

3. Balance O

SO₃²⁻ + H₂O ⟶ SO₄²⁻

Cu²⁺ ⟶ Cu

4. Balance H

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺

Cu²⁺ ⟶ Cu

5. Balance charge

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻

Cu²⁺ + 2e⁻ ⟶ Cu

6. Equalize electrons transferred

1 × [ SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻]

1 × [ Cu²⁺ + 2e⁻ ⟶ Cu]

7. Add the two half-reactions

SO₃²⁻ + H₂O ⟶ SO₄²⁻ + 2H⁺ + 2e⁻]

Cu²⁺ + 2e⁻ ⟶ Cu                                      

SO₃²⁻ + Cu²⁺ + H₂O ⟶ Cu + SO₄²⁻ + 2H⁺

8. Convert to base

SO₃²⁻ + Cu²⁺ + H₂O ⟶ Cu + SO₄²⁻ + 2H⁺

            2H⁺ + 2OH⁻ ⟶ 2H₂O                      

SO₃²⁻ + Cu²⁺ + 2OH⁻ ⟶ Cu + SO₄²⁻ + H₂O

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.